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Table 3 Simulation results for p = 5, Σ1 = Σ2 = Ι(5), N = 1000

From: Estimating misclassification error: a closer look at cross-validation based methods

Method

n

Δ

ē a

ē N

M S E

SD(MSE)

V A R

SD(VAR)

MSB

B I A S

SD(BIAS)

LOOCV

50

1

0.38308

0.38848

0.00688

0.00996

0

0

0.00688

0.00540

0.08281

 

50

3

0.09741

0.10052

0.00227

0.00338

0

0

0.00227

0.00311

0.04760

BCVn

50

1

0.38308

0.27058

0.02073

0.01027

0.00587

0.00162

0.01486

−0.11250

0.04693

 

50

3

0.09741

0.07686

0.00305

0.00167

0.00160

0.00082

0.00145

−0.02055

0.03208

LOOCV

100

1

0.35366

0.35164

0.00291

0.00419

0

0

0.00291

−0.00202

0.05390

 

100

3

0.07962

0.07906

0.00080

0.00110

0

0

0.00080

−0.00056

0.02822

BCVn

100

1

0.35366

0.29312

0.00799

0.00454

0.00308

0.00074

0.00491

−0.06054

0.03529

 

100

3

0.07962

0.06781

0.00141

0.00080

0.00075

0.00031

0.00066

−0.01180

0.02278

k CV10

50

1

0.38308

0.39236

0.00711

0.00860

0.00126

0.00036

0.00585

0.00929

0.07598

 

50

3

0.09741

0.10438

0.00252

0.00327

0.00039

0.00019

0.00213

0.00697

0.04568

BCV10

50

1

0.38308

0.27549

0.01950

0.00968

0.00579

0.00113

0.01371

−0.10758

0.04622

 

50

3

0.09741

0.08135

0.00302

0.00163

0.00173

0.00078

0.00128

−0.01606

0.03202

k CV10

100

1

0.35366

0.35585

0.00299

0.00364

0.00049

0.00012

0.00251

0.00219

0.05003

 

100

3

0.07962

0.08055

0.00085

0.00109

0.00010

0.00005

0.00075

0.00094

0.02735

BCV10

100

1

0.35366

0.29629

0.00756

0.00427

0.00305

0.00041

0.00451

−0.05737

0.03488

 

100

3

0.07962

0.06942

0.00136

0.00072

0.00076

0.00026

0.00060

−0.01020

0.02239

  1. e a = 1 / N i = 1 N e i , e N = 1 / N i = 1 N e Ri , M S B = 1 / N i = 1 N ( e Ri e i ) 2