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Table 4 Distribution of bacteria isolated with respect to currency type, denomination and source

From: Public health implications of contamination of Franc CFA (XAF) circulating in Buea (Cameroon) with drug resistant pathogens

Currency denomination Bacteria isolated N (%)
Bacillus sp Corynebacterium sp Pseudomonas sp Staphylococcus aureus CoNS Shigella dysenteriae Escherichia coli Proteus mirabilis Enterobacter aerogenes
Note 500 6 (2.8) 0 (0.0) 1 (0.5) 3 (1.4) 13 (6.1) 0 (0.0) 2 (0.9) 0 (0.0) 0 (0.0)
1000 7 (3.2) 10 (4.7) 4 (1.8) 10 (4.7) 29 (10.7) 2 (0.9) 4 (1.8) 1 (0.5) 0 (0.0)
2000 3 (1.4) 2 (0.9) 7 (3.2) 12 (5.6) 28 (13.1) 1 (0.5) 1 (0.5) 0 (0.0) 2 (0.9)
5000 4 (1.8) 1 (0.5) 1 (0.5) 2 (0.9) 9 (4.2) 1 (0.5) 2 (0.9) 0 (0.0) 0 (0.0)
10000 1 (0.5) 1 (0.5) 2 (0.9) 5 (2.3) 6 (2.8) 1 (0.5) 3 (1.4) 0 (0.0) 0 (0.0)
Coin 50 4 (1.8) 1 (0.5) 1 (0.5) 5 (2.3) 10 (4.7) 0 (0.0) 3 (1.4) 0 (0.0) 0 (0.0)
100 1 (0.5) 2 (0.9) 2 (0.9) 5 (2.3) 20 (9.4) 1 (0.5) 2 (0.9) 0 (0.0) 0 (0.0)
500 3 (1.4) 1 (0.5) 0 (0.0) 1 (0.5) 2 (0.9) 1 (0.5) 1 (0.5) 0 (0.0) 0 (0.0)
Total 29 (13.6) 18 (8.4) 18 (8.4) 43 (20.1) 117 (54.9) 7 (3.3) 18 (8.4) 1 (0.4) 2 (0.9)
χ 2 -test χ 2  = 13.512df = 7 P = 0.061. χ 2  = 13.610df = 7 P = 0.059 χ 2  = 6.132df = 7P = 0.524 χ 2  = 5.714df = 7P = 0.574. χ 2  = 9.873 df = 7 P = 0.196 χ 2  = 4.063 df = 7 P = 0.773. χ 2  = 5.806 df = 7 P = 0.563. χ 2  = 3.50 df = 7 P = 0.835. χ 2  = 8.027 df = 7 P = 0.330.
Source of currency          
Butchers 2 (0.9) 8 (3.7) 5 (2.3) 11 (5.1) 23 (10.7) 1 (0.5) 2 (0.9) 0 (0.0) 1 (0.5)
Food vendors 6 (2.8) 8 (3.7) 4 (1.8) 9 (4.2) 32 (15.0) 1 (0.5) 3 (1.4) 1 (0.5) 0 (0.0)
Store attendants 1 (0.5) 2 (0.9) 1 (0.5) 3 (1.4) 10 (4.7) 0 (0.0) 4 1.8) 0 (0.0) 1 (0.5)
Students 5 (2.3) 0 (0.0) 2 (0.9) 2 (0.9) 7 (3.2) 1 (0.5) 5 (2.3) 0 (0.0) 0 (0.0)
Hospitals/Clinic 12 (5.6) 0 (0.0) 5 (2.3) 12 (5.6) 39 (18.3) 3 (1.4) 4 (1.8) 0 (0.0) 0 (0.0)
Taxi drivers 3 (1.3) 0 (0.0) 1 (0.5) 6 (2.8) 6 (2.8) 1 (0.5) 0 (0.0) 0 (0.0) 0 (0.0)
Total 29 (13.6) 18 (8.4) 18 (8.4) 43 (20.2) 117 (54.9) 7 (3.2) 18 (8.4) 1 (0.5) 2 (0.9)
χ 2 -test χ 2  = 9.966 df = 7 P = 0.126. χ 2  = 24.399 df = 7 . P < 0.001 χ 2  = 3.920 df = 6 P = 0.688. χ 2  = 10.485 df = 6 P = 0.106. χ 2  = 32.725 df = 6 P < 0.001. χ 2  = 2.549 df = 6 P = 0.863. χ 2  = 15.261 df = 6 P = 0.018. χ 2  = 3.103 df = 6 P = 0.7 χ 2  = 7.362 df = 6 P = 0.289.
  1. N = Number isolated.